WebJul 26, 2024 · Best answer Given: pth term is q and (p + q)th term is 0. To prove: qth term is p. pth term is given by q = a + (p - 1) × d……equation1 (p + q)th term is given by 0 = a + (p + q - 1) × d 0 = a + (p - 1) × d + q × d Using equation1 0 = q + q × d d = - 1 Put in equation1 we get a = q + p - 1 qth term is q + p - 1 + (q - 1) × ( - 1) p Hence proved. WebApr 8, 2024 · The qth term is ${T_q} = b = A + (q - 1)D = (A - D) + qD\;\; \to (2)$ The rth term is${T_r} = c = A + (r - 1)D = (A - D) + rD\;\; \to (3)$ Here we have got two unknowns A and D which are to be eliminated. We multiply (1), (2) and (3) by q – r, r – p and p – q respectively and add them together. $$ \Rightarrow a(q - r) + b(r - p) + c(p - q)$$
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WebJul 20, 2024 · pth term is Step-by-step explanation: Since we have given that (p+q) th term of an AP = m (p-q) th term of an AP = n. So, it becomes, so, it becomes, So, first term would be . So, the value of pth term would be . Hence, pth term is # learn more: If tn denotes the nth term of the series 2+3+6+11+18+.....,then find t50. brainly.in/question/3103109 WebApr 21, 2024 · If pth, qth and rth terms of an A.P are a, b and c respectively, then:- Q10. If a, b, c be in A.P, then ( a − c) 2 ( b 2 − a c) is More Sequences and Series Questions Q1. If n harmonic means are inserted between 1 and r, then 1 s t m e a n n t h m e a n = Q2. The arithmetic mean of 1, 2, 3, 4, …. n numbers will be : Q3.
WebApr 21, 2024 · As we know that, the nth term of an AP is given by: T n = a + (n - 1) × d, where a = first term and d = common difference. Let a be the first term and d is the common difference. \(\Rightarrow \;{a_{p + q}} = a + \left( {p + q - 1} \right) \times d\) ...1) \(\Rightarrow \;{a_{p - q}} = a + \left( {p - q - 1} \right) \times d\) ...2) WebIf p th term of an A.P. is q and its q th term is p. Show that its r th term is (p+q− r). Hard View solution > If the pth term of an A.P. be q and qth term be p, prove that the (p+q)th term is zero. Easy View solution > View more Get the Free Answr app Click a picture with our app and get instant verified solutions
WebIn an A.P, if the p th term is 1/q and q th term is 1/p, prove that the sum of first pq terms is 1/2 (pq + 1), where p ≠ q. Solution: It is known that general term of an A.P is a n = a + (n - 1) d p th term = a n = a + (n - 1) d = 1/q .... (1) q th term = a n = a + (n - 1) d = 1/p .... (2) Subtracting (2) from (1) , we obtain WebIf the pth, qth and rth terms of an A.P. be a, b and c respectively, then prove that a(q−r)+b(r−p)+c(p−q)=0. Medium Solution Verified by Toppr Let A be the first term and D the common difference of A.P. T p=a=A+(p−1)D=(A−D)+pD (1) T q=b=A+(q−1)D=(A−D)+qD ..(2) T r=c=A+(r−1)D=(A−D)+rD ..(3)
WebMar 30, 2024 · Transcript. Example 21 If pth, qth, rth and sth terms of an A.P. are in G.P, then show that (p – q), (q – r), (r – s) are also in G.P. We know that the nth term of AP is a + (n – 1)d i.e. an = a + (n – 1)d It is given that ap, aq, ar & as in GP i.e. their common ratio is same So,𝑎_𝑞/𝑎_𝑝 = (ar )/qq = 𝑎𝑠/𝑎𝑟 We need to show (p – q), (q – r), (r – s) are in ...
WebIf the p t h term of an AP is q and the q t h term is p, prove that its n t h term is ( p + q - n). Solution Step 1: Calculate the common difference. Given: p t h term = q and q t h term = p An AP or arithmetic progression is a sequence of numbers with a common difference between two consecutive numbers. hillman cotterless hitch pinWebIf the sum of p terms of an A. P. is q and the sum of q terms is p, then the sum of p + q terms is . Class 11 >> Applied Mathematics >> Sequences and series >> Arithmetic progression >> If the sum of p terms of an A. P. is q a Question If the sum of p terms of an A. P. is q and the sum of q terms is p, then the sum of p + q terms is ______. A 0 B hillman community schools hillman michiganWebJul 12, 2024 · The pth term of an AP is 1/q and the qth term is 1/p. Show that the sum of its pq terms is 1/2(pq+1). Arithmetic Progression class 10. #arithmeticprogression...... smart financial westchaseWebIf the pth, qth, rth terms of an AP be x, y, z respectively, show that x(q – r) + y(r – p) + z(p – q). Q13. If the pth term of an AP is 1/q and the qth term is 1/p, show that the sum of pq terms is ½(pq + 1). LONG ANSWER TYPE QUESTIONS Q14. In an AP of 50 terms, the sum of first 10 terms is 210 and sum of its last 15 terms is 2565. smart financial statementsWebOct 29, 2024 · pth term of an AP = q qth term = p Prove: nth term of A.P. is (p+q-n). Proof: We know that, nth term of an AP (an) = a + (n - 1)d Hence, a + (p - 1)d = q a + pd - d = q a = q - pd + d -- equation (1) Similarly, a + (q - 1)d = p Substitute the value of a from equation (1). q - pd + d + qd - d = p qd - pd = p - q - d(p - q) = p - q - d = 1 smart financial tipsWebMar 29, 2024 · Show that (q r) a+ (r p)b+ (p q) c = 0 Here we have small a in the equation, so we use capital A for first term We know that, An = A + (n 1) D where An is the nth term of A.P. n is the number of terms A is the first term, D is the common difference It is given that pth term of an AP is a i.e. Ap = a Putting n = p A + (p 1) D = a a = A + (p 1)D … hillman customer serviceWebThe p th, q th and r th terms of an A.P are a,b,c respectively. Show that (q−r)a+(r−p)b+(p−q)c=0. Medium Solution Verified by Toppr Let a= First term of the AP and d= Common difference of the AP Now, a=A+(p−1)d....(1) b=A+(q−1)d....(2) c=A+(r−1)d....(3) Subtracting (2) from (1), (3) from (2) and (1) from (3), we get a−b=(p−q)d....(4) smart financial skip a payment