If the work done in stretching a wire by 1mm
WebIf the work done in stretching a wire by 1 m m is 2 J, the work necessary for stretching another wire of same material but with double radius of cross-section and half the length by 1 m m is: Q. Work done in stretching a wire through 1 mm is 2 J . Web23 nov. 2024 · Now Work done in stretching wire = ½ Load ×Extension. ∴ Work done = ½ × 100 × 4.444 × 10-2. ∴ Work done = 2.222 J. Ans: Work done in stretching wire is 2.222 J. Example – 11: A uniform steel wire of length 3 m and area of cross-section 2 mm² is extended through 3mm. Calculate the energy stored in the wire, if the elastic limit is ...
If the work done in stretching a wire by 1mm
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Web28 apr. 2024 · 3 × 10^(-3) J of work is done in stretching a wire by 1 mm. To find: Work done in stretching the wire by 3mm. Calculation: Considering the wire to have spring … Web31 okt. 2024 · Find the work done in stretching a wire of cross-section 1mm and length 2m ... In stretching a wire work is done against internal restoring forces. This work is stored as elastic potential energy or strain energy. If a force F acts along the length L of the wire or cross section A and stretches it by x then:
WebD-2. If work done in stretching a wire by 1mm is 2J, the work necessary for stretching another wire of same material, but with double the radius and half the length by 1mm in joule is – (A) 1/4 (B) 4 (C) 8 (D) 16 Section (E) : Viscosity E-1. An oil drop falls through air with a terminal velocity of 5 × 10–4m/s. WebWhat is the amount of work done in stretching a wire through $$0.1mm$$, if its length is $$2m$$ and area of cross - section, $$10^-6m^2 ( Y=2 \times10^11 N/m^2)$$ A $$5 \times 10^-1 J$$
WebFind the formula for the work done is stretching a wire and apply it to find the elastic energy stored in a wire originally 5metre long and 1mm in diameter, ... Web19 apr. 2024 · The work per unit volume to stretch the length by 1% of a wire with cross-sectional area 1 mm^2 will be..... [y = 9 × 10^11 (N / m ... 1 answer. A steel wire of 1 m long and 1 mm^2 cross sectional area is hung from rigid end when weight of 1 kg is hung from it. asked Apr 19, 2024 in Physics by Niharika (75.9k points) properties of ...
Web26 feb. 2012 · This force stretches the wire through a small elongation x. Let length of wire = L. Force F produce an extension = x. From the figure. Work done on the wire during stretching = Area covered on the x-axis = Average force × extension. Work done, W = Energy stored. ⇒ Energy stored per unit volume in stretching wire = 0.5 × stress × strain
WebIf the work done in stretching a wire by 1 mm is 2 J, the work necessary for stretching another wire of same material but with double radius of cross-section and half the length … lyn alden ethnicityWeb23 nov. 2024 · Find the work done in stretching a wire of length 2 m and of sectional area 1 mm² through 1 mm if Young’s modulus of the material ... Radius of wire = 2/2 = 1mm = 1 × 10-3 m, Stretching load = 10 kg = 10 × 9.8 N, Young’s modulus of elasticity = Y = 12 × 10 10 N/m², and Poisson’s ratio = σ = 0.35. To Find: Lateral ... kinky boots play synopsisWeb11 nov. 2024 · In stretching a wire work is done against internal restoring forces. This work is stored as elastic potential energy or strain energy. If a force F acts along the length L of the wire or cross section A and stretches it by x then: Y o u n g ′ s M o d u l u s ( Y) = S t r e s s S t r a i n = F / A x / L = F L A x ⇒ F = Y A L x. kinky boots official siteWeb19 jan. 2024 · The work done to stretch a wire or the Elastic Potential Energy is equal to the area of the triangle on a Tension/Extension graph, but can also be expressed as ... 50N are applied to a wire with a radius of 1mm. The wire was 0.7m long, but is now 0.75m long. What is the Young's Modulus for the material the wire is made of? Glass, ... kinky boots nyc final performanceWeb25 mrt. 2024 · The work done in stretching a wire is given as W = (1/2).F.dl F is the force required dl is the increase in length (which remains same in both cases) So, we can have W1 / W2 = [ (1/2).F1.dl] / [ (1/2).F2.dl] 2J / W2 = F1 / F2 W2 =2 x ( F2/F1) (1) Now we know that the force is given as F = Y.A. (dl/l) here Y is the Young's Modulus kinky boots play for kidsWebAnswered: A spring 40mm long is stretched by the… bartleby. Science Advanced Physics A spring 40mm long is stretched by the acceleration of a force. If 10N force is required to stretch the spring through 1mm, then work done in stretching through 40mm is? a) 84J b) 48J c) 24J d) 8J. A spring 40mm long is stretched by the acceleration of a force. kinky boots nyc theaterWebIf the work done by stretching a wire by 1mm is 2J, the work necessary for stretching another wire of the same material but with half the radius of cross section and half the … lynair hotel blackpool